20p^2-100(p)(q)+125q^2=0

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Solution for 20p^2-100(p)(q)+125q^2=0 equation:


Simplifying
20p2 + -100(p)(q) + 125q2 = 0

Multiply p * q
20p2 + -100pq + 125q2 = 0

Reorder the terms:
-100pq + 20p2 + 125q2 = 0

Solving
-100pq + 20p2 + 125q2 = 0

Solving for variable 'p'.

Factor out the Greatest Common Factor (GCF), '5'.
5(-20pq + 4p2 + 25q2) = 0

Factor a trinomial.
5((2p + -5q)(2p + -5q)) = 0

Ignore the factor 5.

Subproblem 1

Set the factor '(2p + -5q)' equal to zero and attempt to solve: Simplifying 2p + -5q = 0 Solving 2p + -5q = 0 Move all terms containing p to the left, all other terms to the right. Add '5q' to each side of the equation. 2p + -5q + 5q = 0 + 5q Combine like terms: -5q + 5q = 0 2p + 0 = 0 + 5q 2p = 0 + 5q Remove the zero: 2p = 5q Divide each side by '2'. p = 2.5q Simplifying p = 2.5q

Subproblem 2

Set the factor '(2p + -5q)' equal to zero and attempt to solve: Simplifying 2p + -5q = 0 Solving 2p + -5q = 0 Move all terms containing p to the left, all other terms to the right. Add '5q' to each side of the equation. 2p + -5q + 5q = 0 + 5q Combine like terms: -5q + 5q = 0 2p + 0 = 0 + 5q 2p = 0 + 5q Remove the zero: 2p = 5q Divide each side by '2'. p = 2.5q Simplifying p = 2.5q

Solution

p = {2.5q, 2.5q}

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